Calculate the concentration of [H+] and [OH-] in 0.002 mol/L of HNO3 solution.

Answer 1

The H^+ in 0.002 M HNO3 is 0.002. There is some H^+ from the ionization of H2O but it is small enough to be ignore. For the OH, use
HOH ==> H^+ + OH^-
Kw = 1E-14 = (H^+)(OH^-)
You know Kw and H^+ (from the HNO3), solve for OH^- in the system.

Answer 2

Please answer