K^+ is 0.2M
......F^- + HOH ==> HF + OH^-
I....0.2............0.....0
C.....-x............x.....x
E...0.2-x...........x.....x
Kb for F^- = (Kw/Ka for HF) = (x)(x)/(0.2-x)
Solve for x = (HF) = (OH^-)
You have OH^-, then Kw = (H^+)(OH^-) so you can solve for (H^+).
All of that gives you K, HF, OH, H and F. Note F = 0.2-x)
Calculate the concentration of all species in a 0.20 M KF solution.
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