Calculate the change in internal energy at 1 atm & 25°C.

H2 (g) + 1/2 O2 (g) ---> H2O (l)
delta(H)= -286 KJ/mol

Okay so i started with the equation:
delta(E) = delta(H) - RTdelta(n)

P= 1 atm
T= 298 K
but i don't exactly know what to do from here..please help thank you.

1 answer

nvm i figure it out :)

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