Calculate the change in heat when 3.05g of water vapor (steam) at 100.0 degrees celsius condenses to liquid water and then cools to 18.50 degrees celsius.

Answer 1

q1 = heat released by steam at 100 C condensing to water at 100 C..
q1 = mass steam x delta Hvap.

q2 = heat released in cooling from 100 C to 18.5 C.
q2 = mass water x specific heat water x (Tfinal-Tinitial).

Total heat released
qtotal = q1 + q2.

Answer 2

1040kj