2Al (s) + 3Cu 2+ (aq) → 2Al 3+ (aq) + 3Cu (s)
Al(s) ==> Al^3+ + 3e Look up Eo oxidation
Cu^2+ + 2e ==> Cu(s) Look up Eo reduction.
For Al you will find it in the standard reduction potential table at something like -3 volts but you need to look it up and use the correct value. I don't remember all of these tables. Then Eo oxidation will be the same number but opposite sign. The cell voltage will be the sum of Eo ox + Eo red = Ecell.
Do the same for the others. Post your work if you get stuck.
Calculate the cell potentials for the following voltaic cells:
2Al (s) + 3Cu 2+ (aq) → 2Al 3+ (aq) + 3Cu (s)
3Mg (s) + 2Al 3+ (aq) → 3Mg 2+ (aq) + 2Al (s)
Mg (s) + Cu 2+ (aq) → Mg 2+ (aq) + Cu (s)
1 answer