Calculate the cell potential for the electrochemical cell consisting of Ag metal in a 0.500 M AgNO3 solution and Fe metal in a 3.0 M Fe(NO3)3 solution.
1 answer
From E = Eo - (0.0592/n)*log(red/ox) for each (one as an oxidation and the other as a reduction) add the two. The total will be Ecell.