Calculate the bond order, the molecular configuration, Number of bonding electrons and Number of anti-bonding electrons for Carbon monoxide

1 answer

Carbon monoxide (CO) is a diatomic molecule with the following properties:

1. Molecular Configuration:

The molecular orbital configuration of CO can be derived from the combination of atomic orbitals of carbon and oxygen. The electron configuration for carbon (C) is \(1s^2 2s^2 2p^2\) and for oxygen (O) it is \(1s^2 2s^2 2p^4\).

In the CO molecule, the molecular orbital filling follows this sequence:

  • The bonding order and orbital energies are similar to homonuclear diatomic molecules.
  • The molecular orbitals in order of increasing energy are:
    • \( \sigma_{1s} \)
    • \( \sigma_{1s}^* \)
    • \( \sigma_{2s} \)
    • \( \sigma_{2s}^* \)
    • \( \sigma_{2p_z} \)
    • \( \pi_{2p_x} \)
    • \( \pi_{2p_y} \)
    • \( \pi_{2p_x}^* \)
    • \( \pi_{2p_y}^* \)

The molecular orbital filling for CO:

  • From Carbon: 2 electrons from \(1s\), 2 from \(2s\), and 2 from \(2p\)
  • From Oxygen: 2 electrons from \(1s\), 2 from \(2s\), and 4 from \(2p\)

The total number of available electrons in CO is \(10\) (6 + 4). The filled orbitals are:

  • \(1s^2\)
  • \(1s^{*2}\)
  • \(2s^2\)
  • \(2s^{*2}\)
  • \(2p_z^2\) (bonding)
  • \(2p_x^2\) (bonding)
  • \(2p_y^0\) (empty)

2. Number of Bonding Electrons:

The bonding electrons are in the bonding molecular orbitals:

  • \( \sigma_{2s} \): 2 electrons
  • \( \sigma_{2p_z} \): 2 electrons
  • \( \pi_{2p_x} \): 2 electrons
  • \( \pi_{2p_y} \): 0 electrons (this is empty)

Total bonding electrons = \(2 + 2 + 2 = 6\)

3. Number of Anti-bonding Electrons:

The anti-bonding electrons are found in the anti-bonding molecular orbitals:

  • \( \sigma_{1s}^* \): 2 electrons (but this is below the reference level and does not facilitate bond formation)
  • \( \sigma_{2s}^* \): 2 electrons
  • \( \pi_{2p_x}^* \): 0 electrons
  • \( \pi_{2p_y}^* \): 0 electrons

Total anti-bonding electrons = \(2 + 2 + 0 + 0 = 4\)

4. Bond Order:

The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] Where \(N_b\) is the number of bonding electrons and \(N_a\) is the number of anti-bonding electrons.

Here, \(N_b = 6\) and \(N_a = 4\), \[ \text{Bond Order} = \frac{(6 - 4)}{2} = \frac{2}{2} = 1 \]

Summary:

  • Molecular Configuration: \( (1s^2) (1s^{*2}) (2s^2) (2s^{*2}) (2p_z^2) (2p_x^2) (2p_y^0) \)
  • Number of Bonding Electrons: 6
  • Number of Anti-bonding Electrons: 4
  • Bond Order: 1

Thus, Carbon monoxide (CO) exhibits a bond order of 3, signifying a triple bond between carbon and oxygen.