Calculate the area of sector of a circle which subtends an angel of 45°at the center of the circle, radius 14cm. Solve this please.

Answer 1

The area of the circle:

A = r² π

The area of sector of a circle:

As = r² π ∙ θ / 360°

In this case:

As = 14² π ∙ 45° / 360° = 196 π ∙ 45° / 45° ∙ 8 = 196 π / 8 =

4 ∙ 49 π / 4 ∙ 2 = 49 / 2 π = 49 ∙ 3.14159 / 2 = 76.968955

As = 76.97 cm²

rounded on two decimal places

Answer 2

OR

45° / 360° = 1 / 8

As = 1 / 8 A = 1 / 8 r² π = 1 / 8 14² π = 196 ∙ 3.14159 / 8 = 76.968955

As = 76.97 cm²

rounded on two decimal places

Answer 3

Calculate the atra of a sector of a cicle which subtends an angle of 45 at the centre of the cicle,radius 14

Answer 4

solve