The area of a sector of a circle is given by:
A = (θ/360)πr²
where θ is the central angle of the sector in degrees, r is the radius of the circle, and π is the constant pi (approximately 3.14).
In this case, θ = 45 degrees and r = 14cm, so we can plug in these values to get:
A = (45/360)π(14)²
A = (1/8)π(196)
A = 24.5π
A ≈ 76.96 cm²
Therefore, the area of the sector is approximately 76.96 cm².
Calculate the area of a sector of a circle which subtends an angle of 45 degree at the centre of the circle, radius 14cm.
1 answer
1 answer