Solutions boil when their vapor pressure = atmospheric pressure, which I assume in this case 760 mm.
At 95 total P = 752
at 96 total P = 779 so looks like 95+ (or 96-). You can interpolate between those two values if you want to get closer but the problem says to estimate so I would answer "a little less than 96".
Calculate the approximate boiling point of a mixture of bromobenzene and water
at atmospheric pressure. A table of vapor pressure of water and bromobenzene at
various temperatures is given.
Vapor Pressures (mmHg)
Temperature(c) Water Bromobenzene
93 588 110
94 611 114
95 634 118
96 657 122
97 682 127
98 707 131
99 733 136
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