This question has come up on here a few times in the past, see for example http://www.jiskha.com/display.cgi?id=1261460213.
You need to start with the babalnced equation.
RCH-OH + NaOCl ==> RC=O + NaCl + H2O
so one mole of NaOCl reacts with one mole of fluorenol.
1. calculate the number of moles of fluorenol you have.
0.150 g/molecular mass of fluorenol
this is the number of moles of NaOCl
2. hence calculate the mass of NaOCl
3. then use the percentage concentration to calculate the volume needed.
calculate the amount (volume) of 6.25% (wt./vol.) NaOCl solution (commercial bleach) required to oxidize 150 mg of 9-fluorenol to 9-fluorenone. Whenever appropriate, use balanced chemical equations as a part of your calculation.
2 answers
can you please explain to me how to use the percentage concentration to calculate volume