Calculate pH, pOH, [H+], [OH-], and Ka for a 0.026 M solution of HI (a strong acid). Please help me :(

Answer 1

strong acid; then it is completely dissociated.

[H]=.026
pH= -log (.026)=1.58
pOH= 14-pH= you do it.
[OH]=1E-14/.026=3.85E-13

Answer 2

thank you! :D