Sulfuric acid, H2SO4, is a strong acid that dissociates completely in water to form two hydrogen ions (H+) and one sulfate ion (SO4^2-).
The balanced chemical equation for the dissociation of sulfuric acid in water is:
H2SO4 -> 2H+ + SO4^2-
Since the concentration of the sulfuric acid is 0.005 M, the concentration of the hydrogen ions will also be 0.005 M.
Therefore, the pH of a 0.005 M H2SO4 solution is equal to the negative logarithm of the hydrogen ion concentration:
pH = -log[0.005] = -log(5x10^-3) = -(-2.30) = 2.30
Therefore, the pH of a 0.005 M H2SO4 solution is 2.30.
Calculate ph of a 0.005M H2SO4 which dissociate completely in water
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