pH = -log(H^+). Calculate H^+. Then
(H^+)(OH^-) = Kw = 1E-14
Calculate OH and H
pH= 12
How to set this up
2 answers
1.0E-14 = [H+] [OH-] = 1E=12 [OH-]
[OH-] = 1E-2 and pOH = 2
[OH-] = 1E-2 and pOH = 2