calculate number of atoms in 0.0082g of gold

Answer 1

To calculate the number of atoms in 0.0082g of gold, we need to know the atomic mass of gold and the Avogadro's number.

The atomic mass of gold (Au) is 196.97 g/mol (grams per mole). This means that one mole of gold atoms weighs 196.97 grams.

Avogadro's number is 6.022 x 10^23 atoms per mole.

To calculate the number of atoms in 0.0082g of gold, we need to convert the mass of gold to moles, and then use Avogadro's number to calculate the number of atoms.

First, we divide the mass of gold by its atomic mass:

0.0082g / 196.97 g/mol = 4.16 x 10^-5 moles

Next, we use Avogadro's number to convert from moles to atoms:

4.16 x 10^-5 moles x (6.022 x 10^23 atoms/mole) = 2.50 x 10^19 atoms

Therefore, there are 2.50 x 10^19 atoms in 0.0082g of gold.