calculate kc for reaction I2 (g)+Cl2 (g)⇌2ICl(g )Kp=81.9 (at 298 K)

Answer 1

Kp = Kc*(RT)^delta n where
dn = nproducts-nreactants
Substitute and solve for Kc.

Answer 2

81.9 because the products is 2 and if you add the reactants up it'll be 2 so 2-2=0 so you multiply R*T and you get 24.45388 and if you take it to the 0tg power it'll be 1 so 81.9/1 is 81.9 and that's your answer