calculate how much strontium fluoride will dissolve in 1L of water given Ksp= 2.5x10^-9 at 25 degree celsius

1 answer

....................SrF2 ==> Sr^2+ + 2F^-
I...................solid...........0.............0
C..................solid...........x.............2x
E...................solid...........x............2x

Kso = (Sr^2+)(F^-)^2
Substitute the E line into Ksp and solve for x = solubility of SrF2 in mols/L. If you want grams/L, then g = mols x molar mass = ?