Calculate how much K3Fe(CN)6 [MW: 329.24] you would need to weigh out to make a 1x10-3 M solution dissolved in 0.2 M NaNO3 in a 100 ml volumetric

Question

so far i have worked out that 0.329 g will give me the 1x10-3 M, but im confused when it is dissolved into the NaNO3.

Answer 1

mols K3Fe(CN)6 = M x L = 1E-3M x 0.100 L = ?
Then grams = mols x molar mass = 1E-4 x 329.24 = 0.032924 g
The NaNO3 provides only the 100 mL volume.
In the end you will have a solution that is 1E-3 M in KeFe(CN)6 and also 0.2 M in NaNO3

Answer 2

NERD Alert!!!