The coefficients tell you that.
2.57 molx Na x (1 mol Na2O2/2 mols Na) = ?
Note how mols Na in the numerator cancels with the mols Na in the denominator. That leaves mols Na2O2 in the numerator as the only unit left; you have converted mols Na to mols Na2O2.
calculate how many moles of the product form when 2.57 mol of Na completely reacts.
Assume that there is more than enough of the other reactant.
2Na(s)+O2(g)→Na2O2(s)
1 answer