Calculate how many joules of energy would be needed to take 2kg of ice at

Question

-5 and turn it all to steam at 100 degees celcius?

Answer 1

first do it all for 1 kg and multiply the answer by 2

-5 to 0
2000 J/kg K * 5 = 10,000 J

melt = 334 *10^3 J = 334,000 J

0 to 100
4190 *100 = 419,000 J

boil = 2256*10^3 = 2,256,000 J
so for 1 kg 3,019,000 J
so for 2 kg 6,038,000 J