Are you sure you are using the same chemical equation I used; i.e., 2NaN3 ==> 2Na + 3N2. If so you haven't done anything wrong. 0.65 gives you the mols N2. Now you convert mols N2 to mols NaN3. That is 0.65 mols N2 x (2 mols NaN3/3 mols N2 = ?
Then grams NaN3 = mols NaN3 x molar mass NaN3.
Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.25 atm at a temperature of 20.0°C. How much sodium azide is needed if the air bag must produce the same pressure at 10.0°C?
20.0°C:
_______ g NaN3
(Work) below
n=PV
-----
RT
I used 25X25X20 And divided by 1000 which gave me 12.5 as
Advised for my L(Volume) then converted 20celsius to K which gave me 293.15K and my constant R .08206 so i think i have everything but my solution is wrong
(1.25atms) X (12.5L)
--------------------- =.65 moles (It says i'm wrong what am i doing?)
(0.08206 X 293.15K)
1 answer
1 answer