Calculate how many grams of MgO that can be produced from 4.58 of Mg metal and 0.99 of O2 gas.
Recall the balanced reaction is:
2 Mg (s) + O2 (g) 2 MgO (s)
And the answers to part one were:
Moles of MgO from 4.58 g Mg = 0.1884
Moles of MgO from 0.99 g O2 = 0.0619
Limiting reagent = O2
Enter the mass of MgO possible (the theoretical yield)
2 answers
What have you done on this problem?
Ben, I did this far below.
http://www.jiskha.com/display.cgi?id=1459199032
http://www.jiskha.com/display.cgi?id=1459199032