Calculate E naught cell for the reaction b
5Cd(s) + 2MnO4-(aq) + 16H+(aq) ==> 5Cd^2+(aq) = 2Mn^2+(aq) + 8H2O(l) given the following standard reduction potentials
MnO4^-(aq) + 8H^+(aq) = 5e^- ==> Mn^2+(aq) + 4 H2O(l) E naught = +1.52V
Cd^2+(aq) + 2e^- ==> Cd(s) E naught = -0.40V
2 answers
Enough freebie help. You need to start showing how you approach these problems.
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