f(t)=c then f'(t)=0 i.e. a derivative of a constant (or number) is zero
f(t)=t^n then f'(t)=nt^(n-1)
you bring the exponent n in front and subtract one from the original exponent
finally, plug in 10 for t
Calculate dy/dx at the point t=10 for the equations:
a) x=5t
b) (t^2)-1
2 answers
a)50
b) 99
b) 99