Calculate dy/dx at the point t=10 for the equations:

Question

a) x=5t
b) (t^2)-1

Answer 1

f(t)=c then f'(t)=0 i.e. a derivative of a constant (or number) is zero

f(t)=t^n then f'(t)=nt^(n-1)
you bring the exponent n in front and subtract one from the original exponent

finally, plug in 10 for t

Answer 2

a)50
b) 99