i got -114.14 kj
can someone confirm this?
Calculate DHo for the oxidation of nitric oxide to nitrogen dioxide,
2 NO(g) + O2(g) --> 2 NO2(g),
from the following data:
DHof[NO(g)] = +90.25 kJ
DHof[NO2(g)] = +33.18 kJ
im confused...can someone help me.
3 answers
-114.14 kJ is correct. From the data given, you have 4 significant figures. If your prof is a stickler for s.f., you should round the number to -114.1 kJ.
But how did you get that?