Calculate Delte G Knot for H20(g) + 1/2 O2 <-> H2O2(g) at 600. K, using the following data:

Question

H2(g) + O2(g) <-> H2O2 (g) K = 2.3 X 10^6 at 600. K
2H2(g) + O2(g) <-> 2H20(g) K= 1.8 X 10^37 at 600. K

Answer 1

Use eqn 1 as is. Take 1/2 of eqn 2 and reverse it. When reversing, the new k is 1/old k and when taking 1/2 we take the square root.
Therefore, k for the reaction you want will be k2/sqrt k1.
Then delta G^o = -RTlnK.

Answer 2

140

Answer 3

How find chemical equivalent of H2O2->H2O+1/2O2?