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Calculate Delta H for the reaction CH4(g)+NH3(g)-->HCN(g)+3H2(g) given,

N2(g)+3H2(g)->2NH3(g) DeltaH=-91.8kj
C(s)+2H2(g)->CH3(g) DeltaH=-74.9kj
h2(g)+2C(s)+N2(g)->2HCN(g) DeltaH=270.3kj

1 answer

Add the reverse of eqn 1 to 2x the reverse of equation 2 to eqn 3, then take 1/2 of the sum. Post your work if you gets stuck.
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