To calculate the pH of a tetraoxosulphate(VI) solution, you first need to determine the concentration of the hydrogen ion.
The chemical formula for tetraoxosulphate(VI) is H2SO4. When tetraoxosulphate(VI) dissociates in water, it produces two hydrogen ions (H+) and one sulfate ion (SO42-).
H2SO4 → 2H+ + SO42-
The concentration of hydrogen ions in a 0.005 mol/dm³ tetraoxosulphate(VI) solution is therefore:
[H+] = 2 x 0.005 mol/dm³
[H+] = 0.01 mol/dm³
To calculate the pH of the solution, you can use the following formula:
pH = -log[H+]
pH = -log(0.01)
pH = 2
Therefore, the pH of a 0.005 mol/dm³ tetraoxosulphate(VI) solution is 2.
Calculate d pH of 0.005mol/dm³ tetraoxosulphate(vi)
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