Calculate boiling point and freezing point of this solution which contains 5.85g of C6H12O6 in 255g H2O. pleasee

Answer 1

i've read formulas to use ro solve this problem but i don't know what delta T means. please tell me what formula to use and what delta T means thaaaank youu

Answer 2

As far as I know, Delta T means the difference in temperature. T final- T initial.

Answer 3

First find molar mass of C6H12O6:
I found it to be 180.1566 g/mol

now find the ratio of moles
5.85/180.1566 = .0325mol

Molality of C6H12O6:
(.0325*1000)/255 = .127

note: the value 1000 is from the density of water which is 1.00g/mL

So freezing point:
delta_T = -k_f * m
k_f = 1.86 for water

so delta_T = -1.86*.127 + 0 = -.236 Celcius

For boiling:
delta_T = k_b*m
where k_b =.512

so

.512*.127 + 100 = 100.065 Celcius

Some check my work

Answer 4

THANK YOU SO MUCH!

Answer 5

please explain more about how to find the molality??

Answer 6

oh i got it thank you!