To calculate the surface area of spheres A and B using the formula \( A = 4\pi r^2 \):
-
For Sphere A (radius \( r = 2 \) in): \[ A_A = 4\pi(2^2) = 4\pi(4) = 16\pi \text{ in}^2 \]
-
For Sphere B (radius \( r = 10 \) in): \[ A_B = 4\pi(10^2) = 4\pi(100) = 400\pi \text{ in}^2 \]
Now, to compare the surface areas:
- Sphere A has a surface area of \( 16\pi \) in².
- Sphere B has a surface area of \( 400\pi \) in².
To find how many times larger Sphere B's surface area is compared to Sphere A's, divide the surface area of Sphere B by that of Sphere A: \[ \frac{A_B}{A_A} = \frac{400\pi}{16\pi} = \frac{400}{16} = 25 \]
Thus, the surface area of Sphere B is 25 times as large as the surface area of Sphere A.
The correct response is: Sphere A has a surface area of 16π in.² and sphere B has a surface area of 400π in.², meaning sphere B's surface area is 25 times as large as sphere A's.