Calculate and compare the surface area of sphere A, which has a radius of 4in and sphere B which has a radius of 10 in. The formula for the surface area of a sphere is 4πr2

(1 point)
Responses

Sphere A has a surface area of 64π in2
and sphere B has a surface area of 400π in2
, meaning sphere B's surface area is 6.25 times as large as sphere A's.
Sphere A has a surface area of 64π in2
and sphere B has a surface area of 400π in2
, meaning sphere B's surface area is 6.25 times as large as sphere A's.

Sphere A has a surface area of 16π in2
and sphere B has a surface area of 40π in2
, meaning sphere B's surface area is 5 times as large as sphere A's.
Sphere A has a surface area of 16π in2
and sphere B has a surface area of 40π in2
, meaning sphere B's surface area is 5 times as large as sphere A's.

Sphere A has a surface area of 8π in2
and sphere B has a surface area of 20π in2
, meaning sphere B's surface area is 2.5 times as large as sphere A's.
Sphere A has a surface area of 8π in2
and sphere B has a surface area of 20π in2
, meaning sphere B's surface area is 2.5 times as large as sphere A's.

Sphere A has a surface area of 4π in2
and sphere B has a surface area of 10π in2
, meaning sphere B's surface area is 4 times as large as sphere A's.
Sphere A has a surface area of 4π in2
and sphere B has a surface area of 10π in2
, meaning sphere B's surface area is 4 times as large as sphere A's.
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1 answer

To calculate the surface area of spheres A and B, we will use the formula for the surface area of a sphere:

\[ \text{Surface Area} = 4\pi r^2 \]

For Sphere A:

  • Radius \( r_A = 4 , \text{in} \)

\[ \text{Surface Area of Sphere A} = 4\pi (4^2) = 4\pi (16) = 64\pi , \text{in}^2 \]

For Sphere B:

  • Radius \( r_B = 10 , \text{in} \)

\[ \text{Surface Area of Sphere B} = 4\pi (10^2) = 4\pi (100) = 400\pi , \text{in}^2 \]

Comparison of Surface Areas:

Now, to compare their surface areas, we need to find out how many times the surface area of sphere B is larger than that of sphere A:

\[ \text{Ratio} = \frac{\text{Surface Area of Sphere B}}{\text{Surface Area of Sphere A}} = \frac{400\pi}{64\pi} = \frac{400}{64} = 6.25 \]

Conclusion:

  • Sphere A has a surface area of \( 64\pi , \text{in}^2 \).
  • Sphere B has a surface area of \( 400\pi , \text{in}^2 \).
  • Sphere B's surface area is 6.25 times as large as sphere A's.

Therefore, the correct response is:

Sphere A has a surface area of 64π in² and sphere B has a surface area of 400π in², meaning sphere B's surface area is 6.25 times as large as sphere A's.