Calculate and compare the surface area of sphere A, which has a radius of 4in and sphere B which has a radius of 10 in. The formula for the surface area of a sphere is 4πr2

(1 point)
Responses

Sphere A has a surface area of 64π in2
and sphere B has a surface area of 400π in2
, meaning sphere B's surface area is 6.25 times as large as sphere A's.
Sphere A has a surface area of 64π in2
and sphere B has a surface area of 400π in2
, meaning sphere B's surface area is 6.25 times as large as sphere A's.

Sphere A has a surface area of 16π in2
and sphere B has a surface area of 40π in2
, meaning sphere B's surface area is 5 times as large as sphere A's.
Sphere A has a surface area of 16π in2
and sphere B has a surface area of 40π in2
, meaning sphere B's surface area is 5 times as large as sphere A's.

Sphere A has a surface area of 8π in2
and sphere B has a surface area of 20π in2
, meaning sphere B's surface area is 2.5 times as large as sphere A's.
Sphere A has a surface area of 8π in2
and sphere B has a surface area of 20π in2
, meaning sphere B's surface area is 2.5 times as large as sphere A's.

Sphere A has a surface area of 4π in2
and sphere B has a surface area of 10π in2
, meaning sphere B's surface area is 4 times as large as sphere A's.
Sphere A has a surface area of 4π in2
and sphere B has a surface area of 10π in2
, meaning sphere B's surface area is 4 times as large as sphere A's.
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1 answer

To calculate the surface area of Sphere A and Sphere B, we can use the formula for the surface area of a sphere:

\[ SA = 4\pi r^2 \]

Surface Area of Sphere A (radius = 4 inches)

\[ SA_A = 4\pi (4^2) = 4\pi (16) = 64\pi \text{ in}^2 \]

Surface Area of Sphere B (radius = 10 inches)

\[ SA_B = 4\pi (10^2) = 4\pi (100) = 400\pi \text{ in}^2 \]

Comparing the Surface Areas

Now, we can compare the surface areas of the two spheres:

\[ \frac{SA_B}{SA_A} = \frac{400\pi}{64\pi} = \frac{400}{64} = 6.25 \]

So, Sphere B's surface area is 6.25 times as large as Sphere A's.

Conclusion

Sphere A has a surface area of \(64\pi \text{ in}^2\) and Sphere B has a surface area of \(400\pi \text{ in}^2\), meaning Sphere B's surface area is 6.25 times as large as Sphere A's.

Thus, the correct response is:

Sphere A has a surface area of 64π in² and sphere B has a surface area of 400π in², meaning sphere B's surface area is 6.25 times as large as sphere A's.