Calculate amount of milliliters of 2.0 M HCl needed to neutralize 0.15 mol of NaOH

Answer 1

Start with a balanced equation

HCl + NaOH -> NaCl

so one mole of HCl reacts with 1 mole of NaOH

Thus we need to find the volume of HCl that contains 0.15 mole of HCl

We can do this my simple proportion

1 litre (or 1000 ml) of HCl contains 2.0 moles

1 ml of HCl containes 0.002 moles

0.5 ml contains 0.001 moles

0.5 ml x 150 contains 0.150 moles