This is a simple solubility product problem although the problem spends a lot of time talking about activity coefficients et al. Since the activity coefficient is 1, all the rest of the problem is meant to confuse. BTW, note the correct spelling of fluorite.
CaF2 ==> Ca^+2 + 2F^-
Ksp = (Ca^+2)(F^-)^2
Set up an ICE chart, substitute into the Ksp expression I have written and solve for Ca^+2. The solubility you obtain will be in moles/L. Change to grams/L by multiplying by molar mass CaF2. Since the activity coefficient is 1.00, then the molar concns of Ca^+2 and F^- will be the activities.
Calculate activities of Ca2+ anf F- and the solubility of flurite in pure water at 25C without regard to possible hydroysis. Assume that all activity coefficients are equal to one. Express the solubility of florite in terms of mol/L and g/100mL?
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