To subtract the two numbers \( 4.8 \times 10^{-3} \) and \( 9.4 \times 10^{-6} \), we first need to express both numbers with the same exponent.
The number \( 4.8 \times 10^{-3} \) can be rewritten in terms of \( 10^{-6} \):
\[ 4.8 \times 10^{-3} = 4.8 \times 10^{-3} \times \frac{10^{3}}{10^{3}} = 4.8 \times 10^{3-6} = 4.8 \times 10^{-3} = 4800 \times 10^{-6} \]
Now we can rewrite:
\[ 4.8 \times 10^{-3} = 4800 \times 10^{-6} \]
Now we perform the subtraction:
\[ 4800 \times 10^{-6} - 9.4 \times 10^{-6} = (4800 - 9.4) \times 10^{-6} = 4790.6 \times 10^{-6} \]
Next, we convert \( 4790.6 \) into scientific notation:
\[ 4790.6 = 4.7906 \times 10^{3} \]
This means that we have:
\[ 4790.6 \times 10^{-6} = 4.7906 \times 10^{3-6} = 4.7906 \times 10^{-3} \]
Now we round to two decimal places:
\[ 4.7906 \approx 4.79 \]
Thus, the final result in scientific notation is:
\[ \boxed{4.79 \times 10^{-3}} \]
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