Calcu-

Question

late the mass of pure acetic acid in 440 mL of
this solution at 20 C.
Answer in units of g.

Answer 1

You must finish the problem.

Answer 2

i came up with the answer of 419 g

Answer 3

Th solution has a density of 1.049g/mL and only 40% of the solution is acetic acid

Answer 4

At normal temperature and pressure, air has
a density of 0.001184 g/mL. What is the mass
of air in a room that is 3.74 m by 3.45 m by
3.93 m?
Answer in units of kg.

Answer 5

For the acetic acid problem I don't think the answer is 419 g. You can check it if you wish.
419 g/440 mL
440 mL with a density of 1.049 g/mL = mass of 440 x 1.049 = 461.6 grams and
(419/461.6)*100 = 90.7%; that isn't 40% so it must not be right.

Answer 6

For the air problem, I would convert each of the length, width, height in meters to cm, multiply to obtain volume in cc, then multiply by density to obtain grams air. Convert to kg.