calcium hydroxide is titrated with nitric acid.What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 ml of 0.0500 M nitric acid?

3 answers

2HNO3 + Ca(OH)2 ==> Ca(NO3)2 + 2H2O
35.00 mL x 0.0500 M = 1.750 mmols HNO3. That will require 1/2 x 1.750 = mmoles Ca(OH)2.
M = mmoles/mL
You have M Ca(OH)2 and mmoles Ca(OH)2, solve for mL Ca(OH)2.

438mL

0.875/0.0200 = 43.75mL

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