CaCO3 ==> CaO + CO2
mols CaCO3 = g/molar mass = 10/100 = 0.1 mol
mols CaO (the residue) after heating is 0.1 mol. Convert to grams.
mols CO2 formed = 0.1 mol. You know 1 mol of any gas @ STP is 22.4 L so convert 0.1 mol to L.
Use PV = nRT to convert to other conditions.
Post your work if you get stuck.
Calcium carbonate of mass 10g was heated until there was no further change
A. Write an equation for the reaction
B. Calculate the mass of the residue
C. Calculate the volume of gas evolved at STP
D. What would be the volume of the gas measured at 15°C and 760mmHg
(C=12, O=16, Ca=40, molar mass of gas at STP is 22.4dm³)
1 answer
1 answer