CaCOs - CO, + CaO

Question

A scientist heats 30 grams of calcium carbonate (CaCO) in the chemical reaction shown. What is the total mass of the products?

Answer 1

To solve this problem, we need to determine the molar mass of each compound involved in the reaction.

The molar mass of CaCO is calculated as follows:
- The molar mass of calcium (Ca) is 40.08 g/mol.
- The molar mass of carbon (C) is 12.01 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol (there are two oxygen atoms).

Therefore, the molar mass of CaCO is:
40.08 g/mol (Ca) + 12.01 g/mol (C) + (16.00 g/mol (O) * 2) = 100.09 g/mol

Since the scientist has 30 grams of CaCO, we need to determine the number of moles involved in the reaction:
30 g / 100.09 g/mol = 0.2998 mol

From the reaction, we can see that 1 mole of CaCO reacts to produce 1 mole of CO and 1 mole of CaO.
Therefore, we will also obtain 0.2998 mol of CO and 0.2998 mol of CaO.

Finally, to determine the mass of the products, we need to multiply the number of moles by their respective molar mass.

The molar mass of CO is 28.01 g/mol. Therefore, the mass of CO is:
0.2998 mol * 28.01 g/mol = 8.4 grams

The molar mass of CaO is 56.08 g/mol. Therefore, the mass of CaO is:
0.2998 mol * 56.08 g/mol = 16.8 grams

The total mass of the products is the sum of the masses of CO and CaO:
8.4 grams + 16.8 grams = 25.2 grams.

Therefore, the total mass of the products is 25.2 grams.