Pay attention to the units.
1) convert 1.9 x 10^10 kg CaO2 to grams by multiplying by 1000
(1.9 x 10^10 kg CaO2)(1000 g/ 1 kg)
2) convert grams CaO2 to moles by dividing my the molar mass of CaO
(__g CaO)/(1 mol/molar mass CaO)
3) convert mol CaO2 to mol CO2 by the mol ratio (look at the coefficient of the balanced equation)
CaCO3 (s) ---> 1 CaO(s) + 1 CO2(g)
there's 1 mol CaO for every 1 mol CO2
(__mol CaO)/ (1 mol CO2/ 1 mol CaO)
4) convert mol CO2 to grams and then to kilograms by first multiplying by the molar mass of CO2 and then dividing by 1000
(__mol CO2)(molar mass CO2/ 1 mol CO2)(1 kg/ 1000 g)
CaCO3 (s) ---> CaO(s) + CO2(g)
Calculate the yearly release of CO2 (in kilograms)to the atmosphere if the annual production of CaO is
1.9 x 10^10 kg
2 answers
1.63x10^10