CaCO3 --- CaO+CO2 the mass of CaCO3 that must be decomposed to give 22g of CO2

Question

Anonymous · Answer

Ca = 112.4 g/mol
C = 12 g/mol
O = 16 g/mol
so
CaCO3 = 112.4+ 12 + 48 = 172.4 g/mol
CO2 = 12 + 32 = 44 g/mol
same mols of each
22 g CO2 * 1 mol / 44g = 1/2 mol
1/2 mol of CaCO3 = (1/2)(172.4 ) = 86.2 grams of CaCO3

DrBob222 · Answer

@ Anonymous. oops. Ca is 40.1. CaCO3 is a nice round number like 100 g/mol. So the method is OK but not the numbers. Tried to think how you got 112 but couldn't.