CaC2 (s) + 2 H20 (g) -> Ca(OH)2 (s) + C2H2 (g)

The complete reaction of 22.7 g of CaC2 requires consumption of ________g of H2O.

I did 22.7 g CaC2* (2/64 mols CaC2) = .709

Right?!?!

1 answer

You are correct that the reaction consumed 0.709 mols H2O; however, the problem asked for grams.