Ca(OH)2(s) −→ CaO(s) + H2O(g)

Given:
Ca(OH)2(s) −→ Ca(s) + O2(g) + H2(g)
∆H = 973.3 kJ/mol
2 Ca(s) + O2(g) −→ 2 CaO(s)
∆H = −1269.8 kJ/mol
2 H2(g) + O2(g) −→ 2 H2O(g)
∆H = −483.6 kJ/mol
Answer in units of kJ/mol.

1 answer

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