C7H6O3+CH3OH→C8H8O3+H2O

Question

In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?

percent is 77.l1%

is this correct?

Answer 1

theoretical yield= 1.50/molmassC7H6O3 * molmassC8H8OH

=1.50/138.12 * 152.14=1.65g

percent yield= 1.31/1.65=.792
check my calcs.