C3H6O + 4O2 --> 3CO2(g) + 3H2O(g) deltaH= -1790kJ

the density of C3H6O is 0.79g/mL. HOw much heat is released by the combustion of 150mL of acetone?

1 answer

grams acetone = volume x density = approx 115 grams but you need a more accurate number than that.

So you get 1790 kJ for 58 g C3H6O; how much will you get from 115 g.

1790 x (115/58) = ? kJ released.
Similar Questions
    1. answers icon 2 answers
    1. answers icon 3 answers
  1. given the following thermochemical equations:4B(s) + 3O2(g) -> 2B2O3(s) deltaH=-2509.1 kJ 2H2(g) + O2(g) -> 2H2O(l)
    1. answers icon 1 answer
  2. how to calculate delta h for the reaction2B(s)+3H2(g)arrow B2H6(g)given the following data: 2B(s)+3/2O2(g)arrowB2O3(s)
    1. answers icon 3 answers
more similar questions