The reaction is exothermic. This can be determined by calculating the change in enthalpy (ΔH) of the reaction.
ΔH = [2(−393.5) + 3(−285.8)] - [(−84.7) + 3(−241.8)]
ΔH = -1341.2 kJ/mol
Since the enthalpy of the reaction is negative, the reaction is exothermic.
c2h6o + 3o2 → 2co2 + 3h2o
Is the reaction endothermic or exothermic?
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