When using gases only in an equation, we don't need to convert to moles but we can use the volume and they is proportional to the moles. Your post doesn't specify but I assume there is enough oxygen to use all of the ethylene.
18 mL C2H2 x (3 moles O2/1 mole C2H4) = ??
c2h4(g) + 3O2(g) -> 2 CO2 (g) + 2 H2O (g)
What volume of oxygen will react with 18 ml of ehtylene, c2h4, assuming that the gases are present at the same temperature and pressure?
1 answer