........C2D3 ==> 2C^3+ + 3D^2+
I.......solid.....0.......0
C.......solid.....2x......3x
E.......solid.....2x......3x
Ksp = (C^3+)^2(D^2+)^3
9.14E-9 = (2x)^2(3x)^3
Solve for x for solubility of C2D3.
Units: Technically the unit is "activity" since Ksp is a thermodynamic value and has no units. Your prof may want M or mols/L
C2D3 has a solubility product constant of 9.14×10−9. What is the molar solubility of C2D3? Express your answer with the appropriate units.
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