//c++ code for auto increment/decrement operators.

Question

#include<iostream>
using namespace std;
int main() {
output a=6
int a=5, b, c, d, e, x=4, z=5, t=6;
b=++a; z=4;
cout<<"a="<<<<<<<endl<<"b="<<b<<endl;
c=x++; t=5;
b=6
x=5
c=4
z=3
cout<<"="<<<<<<endl<<<"c="<<c<<endl;
d=3
d= --z;
t=4
cout<<"="<<<<endl<<"d="<<<<<endl;
e= t--;
e=5
cout<<"t="<<<<<<endl<<"e="<<e<<endl;

Answer 1

The given code has some syntax and logical errors. Here is the corrected version:

```cpp
#include<iostream>
using namespace std;
int main() {
int a=5, b, c, d, e, x=4, z=5, t=6;

b=++a; // Increment a and assign the incremented value to b
cout<<"a="<<a<<endl;
cout<<"b="<<b<<endl;

c=x++; // Assign the current value of x to c and then increment x
cout<<"x="<<x<<endl;
cout<<"c="<<c<<endl;

d= --z; // Decrement z and assign the decremented value to d
cout<<"z="<<z<<endl;
cout<<"d="<<d<<endl;

e= t--; // Assign the current value of t to e and then decrement t
cout<<"t="<<t<<endl;
cout<<"e="<<e<<endl;

return 0;
}
```

Output:
```
a=6
b=6
x=5
c=4
z=4
d=4
t=5
e=6
```

Explanation:
- The `++` operator before a variable increments the value of the variable and then returns the incremented value.
- The `--` operator before a variable decrements the value of the variable and then returns the decremented value.
- The `++` operator after a variable returns the current value of the variable and then increments the value of the variable.
- The `--` operator after a variable returns the current value of the variable and then decrements the value of the variable.