c and d are positive consecutive odd integers whose sum is 240. If c > d, then 1/square root of c=? Help?

Answer 1

c and d are positive consecutive odd integers mean :

c = d + 2 becouse :

if d are odd integers, next integer are d + 2

So:

c + d = 240

d + d + 2 = 240

2 d + 2 = 240 Subtract 2 to both sides

2 d + 2 - 2 = 240 - 2

2 d = 238 Divide both sides by2

d = 238 / 2 = 119

c = d + 2

c = 119 + 2

c = 121

1/square root of c = 1 / square root of 121 = 1 / 11